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Quantitative Aptitude · Lesson 6 of 18 · Updated ·

Simple and Compound Interest — Formulas, Differences and Shortcuts

When you put money in a bank (or borrow it), the extra money paid for using it is called interest.

  • Principal (P): the money at the start
  • Rate (R): % per year
  • Time (T): in years
  • Amount (A): principal + interest

1. Simple vs compound — the picture

Bars for ₹1000 at 10%: simple interest adds ₹100 each year (1100, 1200, 1300) while compound interest gives 1100, 1210, 1331

  • Simple interest (SI): interest is always on the original principal → the same amount every year.
  • Compound interest (CI): each year's interest is added to the principal, so next year you earn interest on interest.

2. Simple interest

SI = P × R × T ÷ 100 A = P + SI

Example 1

Find the SI on ₹8,000 at 6% per year for 3 years.

SI = 8000 × 6 × 3 ÷ 100 = ₹1,440. Amount = ₹9,440.

Example 2

At what rate will a sum double itself in 8 years at simple interest?

Doubling means SI = P. So P = P × R × 8 ÷ 100 → R = 100 ÷ 8 = 12.5%.

Shortcut: at simple interest, money becomes n times in (n − 1) × 100 ÷ R years.

3. Compound interest

A = P × (1 + R/100)ᵀ CI = A − P

Example 3

Find the CI on ₹10,000 at 10% per year for 2 years.

A = 10000 × 1.1 × 1.1 = 12,100. CI = ₹2,100.

Compounded half-yearly or quarterly

  • Half-yearly: use R/2 and 2T
  • Quarterly: use R/4 and 4T

Example 4

Find the amount on ₹20,000 at 10% per year compounded half-yearly for 1 year.

Rate per half-year = 5%, number of periods = 2. A = 20000 × 1.05 × 1.05 = ₹22,050.

4. The CI − SI shortcut (very common)

For the same P and R:

2 years: CI − SI = P × (R/100)² 3 years: CI − SI = P × (R/100)² × (3 + R/100)

Example 5

The difference between CI and SI on a sum for 2 years at 10% is ₹50. Find the sum.

50 = P × (0.1)² = P × 0.01 → P = ₹5,000.

Why it works: in year 2, CI also earns interest on year 1's interest (₹500 on ₹5,000 at 10% → ₹50 extra).

5. Percentage tricks for CI

Compound interest is just successive percentage increase. For 2 years at R%, the total growth is R + R + R²/100.

  • 10% for 2 years → 10 + 10 + 1 = 21%
  • 20% for 2 years → 20 + 20 + 4 = 44%

Example 6

A sum becomes ₹4,840 in 2 years at 10% compound interest. Find the sum.

It grew by 21%, so P × 1.21 = 4840 → P = ₹4,000.

Example 7

A sum doubles in 5 years at compound interest. In how many years will it become 8 times?

8 = 2³, so it needs 3 doublings → 3 × 5 = 15 years.

Rule of 72: money roughly doubles in 72 ÷ R years at compound interest. At 8%, about 9 years.

Common mistakes

  • Using the CI formula for simple interest (or the other way round). Read the question.
  • For half-yearly, forgetting to change both the rate (halve it) and the time (double it).
  • Using CI − SI = P(R/100)² for 3 years. It is only for 2 years.

Quick recap

  • SI = PRT/100, same interest every year.
  • A = P(1 + R/100)ᵀ for CI.
  • CI − SI for 2 years = P(R/100)².
  • 2 years of CI at R% = R + R + R²/100 % growth.
  • If a sum becomes k times in t years (CI), it becomes kⁿ times in n × t years.

Practice what you learned

📝 Quiz: Simple and Compound Interest5 questions · instant answers & explanations · +10 XP · counts towards your free certificateTake the quiz →